let
2-digit integer = 10m+n
the sum of N and the reverse of N is the square of an integer
(10m+n) + (10n +m) = k^2
11(m+n) = k^2
m+n = k^2/11
k= 11
m+n = 11
(m,n) = (2,9) or (3,8) or (4,7) or (5,6) or (6,5) or (7,4) or (8,3) or (9,2)
The number of N =8
ans : C
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