10题求他们的通项公式怎么算啊 求大神指点

2025-05-16 04:03:16
推荐回答(1个)
回答(1):

n为偶数时,
tn=(1/2)t(n-1)=(5/4)(t(n-2)+1)
(tn+5)=(5/4)(t(n-2)+5)
=(5/4)²(t(n-4)+5)
=…
=(5/4)^((n-2)/2)(t2+5)
t1000=(5/4)^499(t1/2+5)=(11/2)(5/4)^499