解: |x-1|+|x-2|<2 ①当x<1时原不等式化为 -(x-1)-(x-2)<2 -2x+31/2 ②当1<=x<=2时原不等式化为 (x-1)-(x-2)<2 12时不等式化为 (x-1)+(x-2)<2 2x-3<2 x<5/2