选 D,看下面的演算: A. (P∧┐P)↔Q <==> ((P∧┐P)→Q)∧(Q→(P∧┐P)) <==> (┐(P∧┐P)∨Q)∧(┐Q∨(P∧┐P)) <==> (1∨Q)∧(┐Q∨0) <==> 1∧┐Q <==> ┐Q D. ┐(Q→P)∧P <==> ┐(┐Q∨P)∧P <==> (Q∧┐P)∧P <==> Q∧0 <==> 0
参考答案错了,你没错