x=2^m+12^m=x-1两边平方(2^m)^2=(x-1)^24^m=(x-1)^2y=3+4^m4^m=y-3所以y-3=(x-1)^2y=(x-1)^2+3即y=x^2-2x+4
m=log (x-1) 2 再把代入y中
X=2^M+1 M=log(2) (X-1) Y=3+4^M 把M代入 及得Y=3+2^(X-1)
x=2^m+1x-1=2^m(x-1)^2=(2^m)^2=4^m=y-3y=(x-1)^2+3