化简求值:(1)6abc-{2a2b-[3abc-(4ab2-a2b)]}(2)2x-y+(2y2-x2)+(x2+2y2)(其中x=1,y=-2

2025-05-18 06:58:52
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回答(1):

(1)原式=6abc-[2a2b-(3abc-4ab2+a2b)]
=6abc-2a2b+3abc-4ab2+a2b
=9abc-a2b-4ab2
(2)原式=2x-y+2y2-x2+x2+2y2
=4y2+2x-y;
当x=1,y=-2时,原式=4×4+2×1+2=20.