已知π<α<2π,cos(α-9π)=-3⼀5,求cot(α-11π⼀2)

已知π&lt;α&lt;2π,cos(α-9π)=-3/5,求cot(α-11π/2)要过程
2025-05-18 10:18:21
推荐回答(2个)
回答(1):

cos(α-9π)=cos(a-π)=cos(π-a)=-cosa=-3/5
cosa=3/5
所以,3π/2<α<2π
sina=-4/5

cot(α-11π/2)
=cot(a-3π/2)
=-cot(3π/2-a)
=-tana
=-sina/cosa
=-(-4/5)/(3/5)
=4/3

回答(2):

cot(α-11π/2)=cot(α+π/2)=-tanα=4/3
cos(α-9π)=-cos(α)=-3/5
sinα=-4/5