不计水平路面的摩擦阻力啊，那就简单了。设索引力为FF=2maa=F/(2m)S=1/2at^2脱钩后F=ma1a1=2a以拖车为参照物：S0=1/2*a1*t1^2=1/2*2a*4t^2=8*S答：两车之间的距离为8S.
